Question
$2 \mathrm{Cu}_2 \mathrm{~S}+3 \mathrm{O}_2 \rightarrow 2 \mathrm{Cu}_2 \mathrm{O}+2 \mathrm{SO}_2$
In this reaction which substance is getting oxidised and which substance is getting reduced? Name reducing agent and oxidising agent.

Answer

Since, oxygen is being added to Cu , therefore $\mathrm{Cu}_2 \mathrm{S}$ is oxidised to $\mathrm{Cu}_2 \mathrm{O}$ and the other reactant i.e. $\mathrm{O}_2$ is getting reduced. Hence, $\mathrm{Cu}_2 \mathrm{S}$ is a reducing agent and $\mathrm{O}_2$ is an oxidising agent.

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