MCQ
$3 \tan ^{-1} a=$_______.
- A$\tan ^{-1}\left(\frac{3 a+a^3}{1+3 a^2}\right)$
- B$\tan ^{-1}\left(\frac{3 a+a^3}{1-3 a^2}\right)$
- C$\tan ^{-1}\left(\frac{3 a-a^2}{1+3 a^2}\right)$
- ✓$\tan ^{-1}\left(\frac{3 a-a^3}{1-3 a^2}\right)$
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