$X :\, 2SO_{2(g)} + O_{2(g)} $ $\rightleftharpoons$ $ 2SO_{3(g)}$
$Y:\, PCl_{5(g)} $ $\rightleftharpoons$ $ PCl_{3(g)} + Cl_{2(g)}$
$Z :\, 2HI_{(g)} $ $\rightleftharpoons$ $ H_{2(g)} + I_{2(g)}$
$N_2 + 3H_2 \rightleftharpoons 2NH_3 \,;$ $K_1$
$N_2 + O_2 \rightleftharpoons 2NO\,;$ $K_2$
$H_2 + 2 O_2 \rightleftharpoons H_2O\,;$ $K_3$
તો પ્રક્રિયા $2NH_3 + \frac{5}{2} \overset K \leftrightarrows 2NO + 3H_2O$ નો સંતુલન અચળાંક $(K)$ ...... થશે.
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લીસ્ટ $X$ |
લીસ્ટ $Y$ |
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(A) $A_{(g)} $ $\rightleftharpoons$ $ B_{(g)}$ + ગરમી |
(i) સંતુલન અચળાંક |
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(B) $r_b/r_f$ |
(ii) નીચા તાપમાને અનુકુલિત |
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(C) $r_f / r_b$ |
(iii)[સંતુલન અચળાંક]$^{-1}$ |
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(D) $2A_{(g)} + B_{(g)} $ $\rightleftharpoons$ $ C_{(g)}$ |
(iv) $A_{(g)} + B_{(g)} $ $\rightleftharpoons$ $ C_{(g)} + D_{(g)}$ |
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(E) દંબાણથી અસર |
(V) $\Delta n < 0$ |
$\left(R=0.083 \,L \operatorname{bar} \,{K}^{-1} \,{~mol}^{-1}\right)$