\({A} \underset{{T}\, 300\, {~K}}{\longrightarrow} {B}\)
\([\Delta {G}]_{{P}, {T}}=-49.4\, {~kJ} / {mol}\)
\(\Delta {H}_{{rxn}}=51.4 \,{~kJ} / {mol}\)
\(\Delta {S}_{{rxn}}=?\)
\(\Rightarrow\) From the relation \([\Delta {G}]_{{P}, {T}}=\Delta {H}-{T} \Delta {S}\)
\(\Rightarrow \Delta S_{\text {rxn }} =\frac{\Delta H_{r x n}-[\Delta G]_{p, T}}{T}\)
\(=\frac{[51.4-(-49.4)] \times 100}{300} \,\frac{{J}}{{mol} {K}}\)
\(\Rightarrow \Delta {S}_{{rxn}} =336\, \frac{{J}}{{mol} {K}}\)
$2{C_8}{H_{18}}(g) + 25{O_2}(g) \to 16C{O_2}(g) + 18{H_2}O(g).$
ત્યારે $\Delta H,\,\Delta S$ અને $\Delta G$ની નિશાની .......... હશે.