\(\alpha=\frac{F R}{I}=\frac{5 F R}{2 M R^{2}}=\frac{5 F}{2 M R}\)

For no slipping, \(R \alpha=a\)

\(\frac{5 F}{2 M}=g \sin \theta-\frac{F}{M} \Rightarrow \frac{F}{M}=\frac{2}{7} g \sin \theta\)

\(a=g \sin \theta \cdot \frac{F}{M}=\frac{5}{7} g \sin \theta=\frac{5}{7} g \sin 30\)

\(=\frac{5}{14} g\)