Question
$\frac{3\text{t}+5}{4}-1=\frac{4\text{t}-3}{5}$
✓
Answer
Given, $\frac{3\text{t}+5}{4}-1=\frac{4\text{t}-3}{5}$ $\frac{3\text{t}+5-4}{4}=\frac{4\text{t}-3}{5}5(3)t + 5 - 4 = 4(4t - 3)$
$5(3t + 1) = 4(4t - 3)$
$15t + 5 = 16t - 12$
$15t - 16t = -12 - 5$
$-t = -17$
$\frac{-\text{t}}{-1}=\frac{-17}{-1} t = 17$
$5(3t + 1) = 4(4t - 3)$
$15t + 5 = 16t - 12$
$15t - 16t = -12 - 5$
$-t = -17$
$\frac{-\text{t}}{-1}=\frac{-17}{-1} t = 17$
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