MCQ
$4.48$ $litre$ of an ideal gas at $1$ $atm$ & $273$ $K$ requires $12$ calorie to raise the temperature by $15\,^oC$ at constant volume. The $C_p$ of the gas is..... $cal$
- A$4$
- ✓$6$
- C$2$
- D$8$
✓
Answer
Correct option: B.
$6$
b
$\mathrm{n}=\frac{4.48}{22.4}=0.2$
$\mathrm{n}=\frac{4.48}{22.4}=0.2$
$C_{v}=\frac{\Delta U}{n . \Delta T}=\frac{12}{0.2 \times 15}=4 \,\mathrm{cal}$
$\mathrm{C}_{\mathrm{P}}=\mathrm{C}_{\mathrm{V}}+\mathrm{R}=4+2=6 \,\mathrm{cal}$
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