MCQ
$5\,g$ of $NaOH$ was dissolved in deionized water to prepare a $450\,mL$ stock solution. What volume (in $mL$ ) of this solution would be required to prepare $500\,mL$ of $0.1\,M$ solution?

Given : Molar Mass of $Na$, $O$ and $H$ is $23,16$ and $1\,g\,mol ^{-1}$ respectively

  • A
    $181$
  • B
    $182$
  • $180$
  • D
    $183$

Answer

Correct option: C.
$180$
c
$M =\frac{5}{40} \times \frac{1000}{450}$

$M _1 V _1= M _2 V _2$

$\left(\frac{5}{40} \times \frac{1000}{450}\right) \times V _1=0.1 \times 500$

$V _1=180$

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