${\text{[}}{{\text{H}}^ + }] = \frac{{1.825}}{{36.5 \times 5}} = \frac{1}{{100}} = 0.01N = {10^{ - 2}}N$
$[O{H^ - }] = \frac{{{K_w}}}{{[{H^ + }]}} = \frac{{{{10}^{ - 14}}}}{{{{10}^{ - 2}}}} = {10^{ - 12}}$
($PbCl_2$ નો $K_{SP}$ $ = 3.2 \times 10^{-8}$; $Pb$ નું પરમાણ્વીય દળ $= 207\, u$)