MCQ
$5 \,ml$ of $N$ $HCl$, $20 \,ml$ of $N/2\,\,{H_2}S{O_4}$ and $30\, ml$ of $N/3\,\,HN{O_3}$ are mixed together and volume made to one litre. The normality of the resulting solution is
- A$N/5$
- B$N/10$
- C$N/20$
- ✓$N/40$
✓
Answer
Correct option: D.
$N/40$
d
(d) $NV = {N_1}{V_1} + {N_2}{V_2} + {N_3}{V_3}$
(d) $NV = {N_1}{V_1} + {N_2}{V_2} + {N_3}{V_3}$
$N \times 1000 = 1 \times 5 + \frac{1}{2} \times 20 + \frac{1}{3} \times 30$
$= 5 + 10 + 10 = 25$
$N = 0.025 = \frac{N}{{40}}$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which species does not exist
Which of these represents the incorrect order of the mentioned property ?
To seprate different fractions of crude oil in petroleum industry, the method used is
Heavy water is obtained by :
Which of the following is a polar molecule ?
Correct name of the compound $C{H_3} - \mathop {\mathop {CH - C{H_3}}\limits_{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} }\limits_{C{H_3}\,\,\,\,\,\,\,\,\,\,\,} $ is
→$2, 4$ -hexadiyne $(C_6H_6)$ is allowed to react with $Li $ in $NH_3 (liq)$. The product obtained is treated with $1$ equivalent of $Cl_2$ in $CCl_4$. Which of the following constitutional isomers are possible products ?
→In the reaction $BF_3 + NH_3 \to F_3B.NH_3$
→$HO - \mathop {C{H_2}}\limits_{(2)} - \mathop {C{H_2}}\limits_{(3)} - F$
→Which conformer of above compound is most stable across $C_2 - C_3$ ?
The dissociation constants of two acids $HA_1$ and $HA_2$ are $3.0 \times 10^{-4}$ and $1.8 \times 10^{-5}$ respectively. The relative strengths of the acids will be
→