MCQ
$50\, mL$ of $0.1\, M$ solution of a salt reacted with $25\, mL$ of $0.1\, M$ solution of sodium sulphite. The half reaction for the oxidation of sulphite ion is
$SO{{_{3}^{2-}}_{\left( aq. \right)}}+{{H}_{2}}{{O}_{\left( l \right)}}\to SO{{_{4}^{2-}}_{\left( aq. \right)}}+2{{H}^{+}}_{\left( aq. \right)}+2{{H}^{+}}_{\left( aq. \right)}+2{{e}^{-}}$
If the oxidation number of metal in the salt was $+3$, what would be the new oxidation number of metal?
- A$0$
- B$1$
- ✓$2$
- D$4$
