MCQ
$50\, mL$ of $0.5\, M$ oxalic acid is needed to neutralize $25\, ml$ of sodium hydroxide solution. The amount ....... gram of $NaOH$ in $50\, mL$ of the given sodium hydroxide solution is
- A$40$
- B$10$
- C$20$
- ✓None of these
✓
Answer
Correct option: D.
None of these
d
Eq. of $(COOH)_2$ $=$ Eq. of $NaOH$
Eq. of $(COOH)_2$ $=$ Eq. of $NaOH$
$50 \times 0.5 \times 2 = 25 \times M \times 1$
Mass of $NaOH$ in $50\, mL$ $ = \frac{{50 \times 2}}{{1000}} \times 40 = 4\,g$
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