MCQ
$50\, mL$ of $2\,N$ acetic acid mixed with $10\, mL$ of $1\,N$ sodium acetate solution will have an approximate $pH$ of $(K_a = 10^{-5})$
- ✓$4$
- B$5$
- C$6$
- D$7$
Meq of $\mathrm{CH}_{3} \mathrm{COONa}=10 \times 1=10$
$\mathrm{pH}=-\log \mathrm{Ka}+\log \frac{[\mathrm{Salt}]}{[\mathrm{Acid}]}$
or $\mathrm{pH}=-\log 10^{-5}+\log \frac{10}{100}=4$
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$S\left( s \right) + {O_2}\left( g \right) \rightleftharpoons S{O_2}\left( g \right);{K_1} = {10^{52}}$
$2S\left( s \right) + 3{O_2}\left( g \right) \rightleftharpoons 2S{O_3}\left( g \right);{K_2} = {10^{129}}$
The equilibrium constant for the reaction $2S{O_2}\left( g \right) + {O_2}\left( g \right) \rightleftharpoons 2S{O_3}\left( g \right)$ is