and vertical components of velocity while striking the ground.
\({v_y} = 0 + 10 \times 10 = 100\,m/s\)
Angle with which it strikes the ground.
\(\theta = {\tan ^{ - 1}}\left( {\frac{{{v_y}}}{{{v_x}}}} \right) = {\tan ^{ - 1}}\left( {\frac{{100}}{{500}}} \right) = {\tan ^{ - 1}}\left( {\frac{1}{5}} \right)\)