Question
5(2 - 3x) - 17(2x - 5) = 16
✓
Answer
5(2 - 3x) - 17(2x - 5) = 16
On expanding the brackets, we get (5 × 2) - (5 × 3x) - (17 × 2x) + (17 × 5) = 16
10 - 15x - 34x + 85 = 16
10 + 85 - 34x - 15x = 16
95 - 49x = 16
Subtracting 95 from both sides, we get -49x + 95 - 95 = 16 - 95
-49x = -79
Dividing both sides by -49, we get
$\frac{-49\text{x}}{49}=\frac{-79}{-49}$
$\text{x}=\frac{79}{49}$
Verification:
Substituting $\text{x}=\frac{79}{49}$ in L.H.S., we get
$=5\Big(2-3\times\frac{79}{49}\Big)-17\Big(2\times\frac{79}{49}-5\Big)$
$=(5\times2)-\Big(5\times3\times\frac{79}{49}\Big)-\Big(17\times2\times\frac{79}{49}\Big)+(17\times5)$
$=10-\frac{1185}{49}-\frac{2686}{49}+85$
$=\frac{490-1185-2686+4165}{49}=\frac{784}{49}=16=\text{R.H.S.}$
$\text{L.H.S.}=\text{R.H.S.}$
Hence, verified.
On expanding the brackets, we get (5 × 2) - (5 × 3x) - (17 × 2x) + (17 × 5) = 16
10 - 15x - 34x + 85 = 16
10 + 85 - 34x - 15x = 16
95 - 49x = 16
Subtracting 95 from both sides, we get -49x + 95 - 95 = 16 - 95
-49x = -79
Dividing both sides by -49, we get
$\frac{-49\text{x}}{49}=\frac{-79}{-49}$
$\text{x}=\frac{79}{49}$
Verification:
Substituting $\text{x}=\frac{79}{49}$ in L.H.S., we get
$=5\Big(2-3\times\frac{79}{49}\Big)-17\Big(2\times\frac{79}{49}-5\Big)$
$=(5\times2)-\Big(5\times3\times\frac{79}{49}\Big)-\Big(17\times2\times\frac{79}{49}\Big)+(17\times5)$
$=10-\frac{1185}{49}-\frac{2686}{49}+85$
$=\frac{490-1185-2686+4165}{49}=\frac{784}{49}=16=\text{R.H.S.}$
$\text{L.H.S.}=\text{R.H.S.}$
Hence, verified.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Suvidya borrowed a sum of Rs 30000 at 8 p.c.p.a. interest for a year from her bank to buy a computer. At the end of the period, she had to pay back an amount of Rs 2400 over and above what she had borrowed.
Based on this information fill in the blanks below.
Based on this information fill in the blanks below.
- Principal = Rs__
- Rate of interest =__%
- Interest = Rs__
- Time =__year.
- The total amount returned to the bank = 30,000 + 2,400 = Rs__
Various modes of transport used by 1850 students of a school are given below:
Draw a bar graph to represent the above data.
|
School bus
|
Private bus
|
Bicycle
|
Rickshaw
|
By foot
|
|
640
|
360
|
490
|
210
|
150 |
Find the time when:
A sum of money put at 11% per annum amounts to Rs. 4491 in 2 years 3 months, what will it amount to in 3 years at the same rate?
A sum of money put at 11% per annum amounts to Rs. 4491 in 2 years 3 months, what will it amount to in 3 years at the same rate?
In the given figure $\text{l || m}$ and t is a transversa. If $\angle1\ \text{and}\ \angle2$ are in the ratio 5 : 7 find the measure of each of the angles $\angle1,\ \angle2,\ \angle3\ \text{and}\ \angle8.$
→Complete the following multiplication table:
ls the multiplication table symmetrical about the diagonal joining the upper left corner to the lower right corner?
|
Second number
|
||||||||||
|
First number
|
x
|
-4
|
-3
|
-2
|
-1
|
0
|
1
|
2
|
3
|
4
|
|
-4
|
|
|
|
|
|
|
|
|
|
|
|
-3
|
|
|
|
|
|
|
|
|
|
|
|
-2
|
|
|
|
|
|
|
|
|
|
|
|
-1
|
|
|
|
|
|
|
|
|
|
|
|
0
|
|
|
|
|
|
|
|
|
|
|
|
1
|
|
|
|
|
|
|
|
|
|
|
|
2
|
|
|
|
|
|
|
|
|
|
|
|
3
|
|
|
|
|
|
|
|
|
|
|
|
4
|
|
|
|
|
|
|
|
|
|
|
In the given figure. DE || BC. If $\angle\text{C}=65^\circ$ and $\angle\text{B}=55^\circ$, find
→- $\angle\text{ADE}$
- $\angle\text{AED}$
- $\angle\text{C}$
Jaya, Seema, Nikhil and Neelesh put in altogether Rs 360000 to form a partnership, with their investments being in the proportion 3 : 4 : 7 : 6. What was Jaya’s actual share in the capital? They made a profit of 12%. How much profit did Nikhil make ?
Draw any $\triangle\text{ABC}.$ Bisect side AB at D. Through D, draw a line parallel to BC, meeting AC in E. Measure AE and EC.
→Waht should be added to $5\frac{4}{15}$ to get $12\frac{3}{5}?$
→Draw a line PQ. Draw another line parallel to PQ at a distance of 3cm from it.