Question
In the given figure. DE || BC. If $\angle\text{C}=65^\circ$ and $\angle\text{B}=55^\circ$, find
- $\angle\text{ADE}$
- $\angle\text{AED}$
- $\angle\text{C}$
✓
Answer
- DE || BC
- Sum of the angles of any triangle is $180^\circ$.
$\angle\text{C}=180^\circ-(65^\circ-55^\circ)=60^\circ$
DE || BC
$\therefore \angle\text{AED}=\angle\text{ACB}=60^\circ$ (corresponding angles)
- We have found in point (ii) that $\angle\text{C}=60^\circ$
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