${\mkern 1mu} \bar v{\mkern 1mu} = {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \frac{1}{\lambda }{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \Rightarrow {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \bar v{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} = {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \frac{1}{{5800\,\mathop A\limits^o }}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \Rightarrow {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \bar v{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} = {\mkern 1mu} {\mkern 1mu} \frac{1}{{5800{\mkern 1mu} \times {\mkern 1mu} {{10}^{ - 8}}{\mkern 1mu} cm}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} ({\mkern 1mu} {\mkern 1mu} \because {\mkern 1mu} {\mkern 1mu} 1{\mkern 1mu} \mathop A\limits^o {\mkern 1mu} {\mkern 1mu} = {\mkern 1mu} {\mkern 1mu} {10^{ - 8}}{\mkern 1mu} cm)$
$\begin{gathered}
\Rightarrow \,\,\frac{{{{10}^8}}}{{5800\,\,}}\,c{m^{ - 1}}\,\,\, \Rightarrow \,\,17241.44\,\,c{m^{ - 1}} \hfill \\
v\,\, = \,\,c\bar v\,\,\,\,\, \Rightarrow \,\,\,\,3\, \times \,{10^{10}}\,cm\,{s^{ - 1}}\,\, \times \,\,\,1.7\, \times \,{10^4}\,c{m^{ - 1}}\,\,\, = \,\,3\,\, \times \,\,1.7\, \times \,{10^{14}}\,\,\, = \,\,\,5.1\, \times \,{10^{14}}\,{s^{ - 1}} \hfill \\
\end{gathered} $
આપેલ છે: ઇલેક્ટ્રોનનું દળ $=9.1 \times 10^{-31}\, {~kg}$
ઇલેક્ટ્રોનનો વીજભાર $=1.6 \times 10^{-19}\, {C}$
પ્લાન્ક અચળાંક $=6.63 \times 10^{-34\,} {Js}$