\(d =\sqrt{2 \times 6400 \times h \times 10^{-3}}( h\) in \(m )\)
Area \(=\pi d ^{2}\)
\(=\left(\pi \times 2 \times 6400 \times h \times 10^{-3}\right) km ^{2}\)
\(6.03 \times 100000=100 \times \pi \times 2 \times 6400 \times 10^{-3} h\)
\(h =\frac{6.03 \times 10^{5}}{10 \times \pi \times 128}\)
\(h =150\,m\)