$2VO + 3Fe_2O_3 → 6FeO + V_2O_5 (V = 51, Fe = 56)$
મોલ $\frac{{{\rm{6}}{\rm{.7}}}}{{{\rm{67}}}}\,\,\,\,\,\,\,\,\,\,\,\frac{{48}}{{160}}$
મર્યાદિત $\frac{{{\rm{6}}{\rm{.7}}}}{{{\rm{67}} \times {\rm{2}}}}\,\,\,\,\,\,\frac{{4.8}}{{160 \times 3}}$
$0.05\,\,\,\,\,\,\,\,\,\,0.01$
$FeO$ ના મોલ $ = \,\,{\rm{2}} \times \frac{{{\rm{4}}{\rm{.8}}}}{{{\rm{160}}}};\,$
$FeO$ નું વજન $ = \frac{{{\rm{2}} \times {\rm{4}}{\rm{.8}}}}{{{\rm{160}}}} \times 72 = 4.32\,g$