MCQ
$74.5 \,g$ of a metallic chloride contain $35.5\, g$ of chlorine. The equivalent weight of the metal is
- A$19.5$
- B$35.5$
- ✓$39$
- D$78$
✓
Answer
Correct option: C.
$39$
c
(c) wt. of metallic chloride$ = 74.5$
(c) wt. of metallic chloride$ = 74.5$
wt. of chlorine = $35.5 $
$\therefore $ wt. of metal $ = 74.5 - 35.5 = 39$
Equivalent weight of metal $ = \frac{{{\rm{weight of metal}}}}{{{\rm{weight of chlorine}}}} \times 35.5$
$ = \frac{{39}}{{35.5}} \times 35.5 = 39$
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