MCQ
$7.5$ grams of a gas occupy $5.8$ litres of volume at $STP$ the gas is
- ✓$NO$
- B${N_2}O$
- C$CO$
- D$C{O_2}$
$\therefore $ $22.4\,L$ of gas has mass =$\frac{{7.5}}{{5.8}} \times 22.4 = 28.96$
So molecular weight = $29$
So, molecular formula of compound is $NO$
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$\begin{array}{*{20}{c}}
{R = - CH - Cl}\\
{|\,\,}\\
{\,\,\,\,C{H_3}}
\end{array}\,\,\,\,,\,\,\,\,\,\,\,\,\,\,\begin{array}{*{20}{c}}
{S = - CH - Cl}\\
{|\,\,}\\
{Br}
\end{array}$