So $1$ faraday = $96500\, C$ are required to liberate $9\, gm$ of $Al$.
$(i)$ $A + e \rightarrow A^{-} ; E^o= -0.24 V$
$(ii)$ $B^{-} + e \rightarrow B^{2-}; E^o = + 1.25 V$
$(iii)$ $C^{-} + 2e \rightarrow C^{3-}; E^o = -1.25 V $
$(iv)$ $D + 2e \rightarrow D^{2-}; E^o = + 0.68 V$
$mol^{-1}, ᴧ^{0}\, KCl = 150\, S\, cm^{2}\, mol^{-1}$ હોય, તો $ᴧ^{0}\, NaBr$ .............. ${\rm{S}}\,{\rm{c}}{{\rm{m}}^2}{\rm{mo}}{{\rm{l}}^{ - 1}}$ શોધો.