MCQ
$9.0\, gm$  of ${H_2}O$ is vaporised at ${100\,^o}C$ and  $1 \,atm$  pressure. If the latent heat of vaporisation of water is $x\,J/gm$, then $\Delta S$ is given by
  • A
    $\frac{x}{{373}}$
  • B
    $\frac{{18x}}{{100}}$
  • C
    $\frac{{18x}}{{373}}$
  • $\frac{1}{2} \times \frac{{18x}}{{373}}$

Answer

Correct option: D.
$\frac{1}{2} \times \frac{{18x}}{{373}}$
d
Let the $\Delta C _{ v }$ be $x$

$\Delta S =\frac{\Delta H }{ T }$

$\Delta S =\frac{ m \Delta C _{ V }}{ T }$

$\Delta S =\frac{9 x }{373}=\frac{1}{2} \times \frac{18 x }{373}$

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