MCQ
$(-9)^3÷ (-9)^8$ is equal to:
  • A
    $ (9)^5 $
     
  • B
    $ (9)^{-5} $
     
  • C
    $ (-9)^5 $
     
  • $ (-9)^{-5} $

Answer

Correct option: D.
$ (-9)^{-5} $
Given,$(-9)^3\div (-9)^8$
Using law of exponents,
$a^m+ a^n= (a)^{m-n} [\because$ a is non$-$zero integer$]$
$\therefore (-9)^3+ (-9)^8$
$= (-9)^{3-8}$
$ (-9)^{-5} $

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