$9.72\ g$ of potassium chloride dissolves in $30g$ of water at $70^\circ\ C$. Calculate the solubility of potassium chloride at that temperature.
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$9.72\ g$ of $KCl$ dissolves in $30\ g$ of water.
So, amount of $KCl$ which gets dissolved in $100\ g$ of water $=\frac{9.72\times100}{30} = 32.4\text{g}$
Thus, the solubility of $KCl = 32.4\ g$
So, amount of $KCl$ which gets dissolved in $100\ g$ of water $=\frac{9.72\times100}{30} = 32.4\text{g}$
Thus, the solubility of $KCl = 32.4\ g$
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