A $10\ \mu F$ capacitor is charged to a potential difference of $1000\ V$. The terminals of the charged capacitor are disconnected from the power supply and connected to the terminals of an uncharged $6\ \mu F$ capacitor. What is the final potential difference across each capacitor.....$V$
Medium
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(c) After charging, total charge on the capacitor $Q = CV$
$= 10 \times 10^{-6} \,F \times 1000 V = 10^{-2} \,C.$
Common potential $V = \frac{{{C_1}{V_1}}}{{{C_1} + {C_2}}}$$ = \frac{{{{10}^{ - 2}}}}{{16 \times {{10}^{ - 6}}}}= 625\,V.$
$= 10 \times 10^{-6} \,F \times 1000 V = 10^{-2} \,C.$
Common potential $V = \frac{{{C_1}{V_1}}}{{{C_1} + {C_2}}}$$ = \frac{{{{10}^{ - 2}}}}{{16 \times {{10}^{ - 6}}}}= 625\,V.$
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