Question
A 12pF capacitor is connected to a 50V battery. How much electrostatic energy is stored in the capacitor?
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Answer
Capacitor of the capacitance, $C = 12 pF = 12 \times 10^{-12} F$
Potential difference, $V = 50 V$
Electrostatic energy stored in the capacitor is given by the relation,
$\text{E}=\frac{1}{2}\text{CV}^2$
$=\frac{1}{2}\times12\times10^{-12}\times(50)^2$
$= 1.5 \times 10^{-8} J$
Therefore, the electrostatic energy stored in the capacitor is $1.5 \times 10^{-8} J.$
Potential difference, $V = 50 V$
Electrostatic energy stored in the capacitor is given by the relation,
$\text{E}=\frac{1}{2}\text{CV}^2$
$=\frac{1}{2}\times12\times10^{-12}\times(50)^2$
$= 1.5 \times 10^{-8} J$
Therefore, the electrostatic energy stored in the capacitor is $1.5 \times 10^{-8} J.$
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