A $2 \,kg$ mass starts from rest on an inclined smooth surface with inclination $30^°$ and length $2\, m$. ...... $m$ will it travel before coming to rest on a frictional surface with frictional coefficient of $0.25$
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(a)${v^2} = {u^2} + 2as = 0 + 2 \times g\sin 30$$ \times 2$ $⇒$ $v = \sqrt {20} $
Let it travel distance ‘S’ before coming to rest
$S = \frac{{{v^2}}}{{2\mu g}} = \frac{{20}}{{2 \times 0.25 \times 10}} = 4\,m$
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