A $2\, m$ long rod of radius $1\, cm$ which is fixed from one end is given a twist of $0.8$ radians. The shear strain developed will be
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(b) $r\theta = L\varphi \Rightarrow {10^{ - 2}} \times 0.8 = 2 \times \varphi \Rightarrow \varphi = 0.004$
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