Question
A $3 kg$ block, attached to a spring, performs linear SHM with the displacement given by $x =2$ $\cos (50 t ) m$. Find the spring constant of the spring.

Answer

Data : $m=3 kg , x =2 \cos (50 t ) m$
Comparing the given equation with $x = A \cos \omega t$,
$ \omega=50 rad / s$
$\omega^2= k / m $
$\therefore$ The spring constant,
$ k =m \omega^2=(3)(50)^2$
$=3 \times 2500=7500 N / m $

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