A $30\,\mu F$ capacitor is charged by a constant current of $30\, mA$. If the capacitor is initially uncharged, how long does it take for the potential difference to reach $400\, V$.....$s$
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$\mathrm{Q}=\mathrm{CV}=30 \times 10^{-6} \times 400=12 \times 10^{-3} \mathrm{\,C}$
$\mathrm{t}=\frac{\mathrm{Q}}{\mathrm{I}}=\frac{12 \times 10^{-3}}{30 \times 10^{-3}}=0.4 \mathrm{\,sec}$
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