Five identical plates each of area $A$ are joined as shown in the figure. The distance between the plates is $d$. The plates are connected to a potential difference of $V\;volts$. The charge on plates $1$ and $4$ will be
  • A$\frac{{{\varepsilon _0}AV}}{d}.\frac{{2{\varepsilon _0}AV}}{d}$
  • B$\frac{{{\varepsilon _0}AV}}{d}.\frac{{2{\varepsilon _0}AV}}{d}$
  • C$\,\frac{{{\varepsilon _0}AV}}{d}.\frac{{ - 2{\varepsilon _0}AV}}{d}$
  • D$\frac{{ - {\varepsilon _0}AV}}{d}.\frac{{ - 2{\varepsilon _0}AV}}{d}$
IIT 1984, Diffcult
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