A $4\,\mu F$ condenser is connected in parallel to another condenser of $8\,\mu F$. Both the condensers are then connected in series with a $12\,\mu F$ condenser and charged to $20\;volts$. The charge on the plate of $4\,\mu F$ condenser is......$\mu C$
Medium
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(b) Equivalent capacitance of the circuit ${C_{eq}} = 6\,\mu F$
Charge supplied from source $Q = 6 × 20 =120 \,µC$
Hence charge on the plates of $4 \,µF$ capacitor
$ = Q' = \frac{4}{{(4 + 8)}} \times 120 = 40\,\mu C$
Charge supplied from source $Q = 6 × 20 =120 \,µC$
Hence charge on the plates of $4 \,µF$ capacitor
$ = Q' = \frac{4}{{(4 + 8)}} \times 120 = 40\,\mu C$
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