A sphere of radius $1\,cm$ has potential of $8000\,V$, then energy density near its surface will be
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(d) Energy density ${u_e} = \frac{1}{2}{\varepsilon _0}{E^2} = \frac{1}{2} \times 8.86 \times {10^{ - 12}} \times {\left( {\frac{V}{r}} \right)^2}$
$= 2.83\, J/m^3$
$= 2.83\, J/m^3$
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