A $5.0\, \mu F$ capacitor is charged to a potential difference $800\, V$ and discharged through a conductor. The energy(in $J$) given to a conductor during the discharge is
AIIMS 2019, Medium
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The energy of conductor during discharge is calculated as,
$U=\frac{1}{2} C V^{2}$
$=\frac{1}{2}(5.0 \mu F )(800 V )^{2}$
$=\frac{1}{2}\left(5.0 \mu F \times \frac{1 F }{10^{6} \mu F }\right)(800 V )^{2}$
$=1.6$ Joule
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