The charge on capacitor of capacitance $15 \mu F$ in the figure given below is $\dots \; \mu c$
JEE MAIN 2022, Medium
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$\frac{1}{ C _{ eq }}=\frac{1}{10}+\frac{1}{15}+\frac{1}{20}=\frac{12+8+6}{120}=\frac{26}{120}$
$C _{ eq }=\frac{60}{13} \,\mu F$
$Q =\frac{13 \times 60}{13}=60 \,\mu C$
Charge on each capacitor is same
$\because$ they are in series.
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