MCQ
A $500 W$ heating unit is designed to operate from a 115 volt line. If the line voltage drops to 110 volt, the percentage drop in heat output will be
  • A
    $10.20 \%$
  • B
    $8.1 \%$
  • $8.6 \%$
  • D
    $7.6 \%$

Answer

Correct option: C.
$8.6 \%$
(c)$P_{\text {consumed }}=\left(\frac{V_A}{V_R}\right)^2 \times P_R=\left(\frac{110}{115}\right)^2 \times 500=457.46 \mathrm{~W}$So, percentage drop in power output$=\frac{(500-457.46)}{500} \times 100=8.6 \%$

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