MCQ
A $60\, watt$ bulb operates on $220\,V$ supply. The current flowing through the bulb is
- A$11/3\, amp$
- ✓$3/11\, amp$
- C$3\, amp$
- D$6\, amp$
✓
Answer
Correct option: B.
$3/11\, amp$
b
(b) $P = Vi \Rightarrow i = \frac{P}{V} = \frac{{60}}{{220}} = \frac{3}{{11}}amp$
(b) $P = Vi \Rightarrow i = \frac{P}{V} = \frac{{60}}{{220}} = \frac{3}{{11}}amp$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Rutherford’s $\alpha$-particle experiment showed that the atoms have
→In the circuit shown in figure, the $AC$ source gives a voltage $V = 20\, \cos \,(2000t)$. Neglecting source resistance, the voltmeter and ammeter readings will be
→Activity of radioactive element decreased to one third of original activity $\mathrm{R}_0$ in 9 years. After further 9 years, its activity will be
→The magnetic field due to a short magnet at a point on its axis at distance X cm from the middle point of the magnet is 200 Gauss. The magnetic field at a point on the neutral axis at a distance X cm from the middle of the magnet is
The force acting between proton and proton inside the nucleus is
The radius of a nucleus is given by $r_0 A^{1 / 3}$, where $r_0=1.3 \times 10^{-15} \,m$ and $A$ is the mass number of the nucleus. The lead nucleus has $A=206$. The electrostatic force between two protons in this nucleus is approximately ................ $N$
→Which of the following statement is true
The charge on 500 cc of water due to protons will be
In the circuit shown in the figure, the current through
A single slit Fraunhoffer diffraction pattern is formed with white light. For what wavelength of light the third secondary maximum in the diffraction pattern coincides with the second secondary maximum in the pattern for red light of wavelength $6500{\text{ }}\mathop {\text{A}}\limits^o $?........$\mathop A\limits^o $
→