A $6.0\,volt$ battery is connected to two light bulbs as shown in figure. Light bulb $1$ has resistance $3\,ohm$ while light bulb $2$ has resistance $6\,ohm.$ Battery has negligible internal resistance. Which bulb will glow brighter?
AIEEE 2012, Diffcult
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Total resistance $=\frac{6 \times 3}{6+3}=2 \,\Omega$
Current in circuit $=\frac{6}{2}=3 \,\mathrm{A}$
Therefore current through bulb $1$ is $2 \,A$ and bulb $2$ is $1\, A .$ So bulb $1$ will glow more
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