
$I=\frac{1.5-1.3}{r_{1}+r_{2}}=\frac{0.2}{r_{1}+r_{2}}$
$\mathrm{V}=1.3+\mathrm{Ir}_{1}$
$1.45=1.3+\frac{0.2 \mathrm{r}_{1}}{\mathrm{r}_{1}+\mathrm{r}_{2}}$
$\Rightarrow 0.15=\frac{0.2 \mathrm{r}_{1}}{\mathrm{r}_{1}+\mathrm{r}_{2}}$
$\Rightarrow 3\left(\mathrm{r}_{1}+\mathrm{r}_{2}\right)=4 \mathrm{r}_{1}$
$\Rightarrow 3 r_{2}=r_{1}$


$(2)$ The product of a volt and an ampere is a joule/second.
$(3)$ The product of volt and watt is horse power.
$(4)$ Watt-hour can be measured in terms of electron volt.
State if
