Question
A ball of mass $m$ moving with speed $u$ collides with a smooth horizontal surface at angle $\theta$ with it as shown in figure. The magnitude of impulse imparted to surface by ball is [Coefficient of restitution of collision is $e$]

Answer

(d)

$u_y=-u \sin \theta \hat{j}$

$\vec{v}_y=+e u \sin \theta \hat{j}$

$\vec{I}=m\left(\vec{v}_y-\vec{u}_y\right)$

$=m u(e+1) \sin \theta$

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