Rate of cooling $\propto$ Mean temperature difference
==> $\frac{{{\rm{Fall in}}\,{\rm{temperature}}}}{{{\rm{Time}}}} \propto \left( {\frac{{{\theta _1} + {\theta _2}}}{2} - {\theta _0}} \right)$
${\left( {\frac{{{\theta _1} + {\theta _2}}}{2}} \right)_1} > {\left( {\frac{{{\theta _1} + {\theta _2}}}{2}} \right)_2} > {\left( {\frac{{{\theta _1} + {\theta _2}}}{2}} \right)_3}$
==> ${T_1} < {T_2} < {T_3}$
$Reason :$ The thermal conductivity of brass is more than the thermal conductivity of wood.