$v = \sqrt {2as} $$ = \sqrt {2gl(\sin \theta - \mu \cos \theta )} $
$STATEMENT-2$ The magnitude of frictional force depends on the nature of the two surfaces in contact.
(considering $4\ kg$ block doesn't fall on ground)
Consider the following statements
$(i)$ Time when relative motion between them is stopped is $1.4\ second$.
$(ii)$ Time when relative motion between them is stopped in $1.2\ second$
$(iii)$ The common velocity of the two blocks is $8\ m/s$, towards right.
$(iv)$ The displacement of the $4\, kg$ block when relative motion stopped is$10.8\ m$.
Which of the fstatements is/are correct