A block is placed on a frictionless horizontal table. The mass of the block is m and springs are attached on either side with force constants ${K_1}$ and ${K_2}$. If the block is displaced a little and left to oscillate, then the angular frequency of oscillation will be
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(a)In this case springs are in parallel, so${k_{eq}} = {k_1} + {k_2}$
and $\omega = \sqrt {\frac{{{k_{eq}}}}{m}} = \sqrt {\frac{{{k_1} + {k_2}}}{m}} $
and $\omega = \sqrt {\frac{{{k_{eq}}}}{m}} = \sqrt {\frac{{{k_1} + {k_2}}}{m}} $
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