Question
The angular amplitude of a simple pendulum is $\theta_0$. The maximum tension in its string will be

Answer

(d)

Maximum tension in the string is

$T_{\max }=m g+\frac{m v^2}{l}$

$=m g+\frac{2 m g l}{l}\left(1-\cos \theta_0\right)$

$=m g+2 m g\left(1-1+\frac{\theta_0^2}{2}\right) \text { (since } \theta_0 \text { is small) }$

$=m g\left(1+\theta_0^2\right)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions