A boat carrying steel balls is floating on the surface of water in a tank. If the balls are thrown into the tank one by one, how will it affect the level of water
Easy
Download our app for free and get started
(c) When steel balls in boat, volume of water displaced
$V_{1}=\frac{M+m}{\rho_{\omega}}$
When steel balls $\operatorname{sink}, V_{2}=\frac{M}{\rho_{\omega}}+\frac{M}{\sigma_{s}}$
$\sigma_{s}>\rho_{\omega}, V_{2} < V_{1},$ level will fall.
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A solid sphere of radius $R$ and density $\rho$ is attached to one end of a mass-less spring of force constant $k$. The other end of the spring is connected to another solid sphere of radius $R$ and density $3 p$. The complete arrangement is placed in a liquid of density $2 p$ and is allowed to reach equilibrium. The correct statement$(s)$ is (are)View Solution
$(A)$ the net elongation of the spring is $\frac{4 \pi R^3 \rho g}{3 k}$
$(B)$ the net elongation of the spring is $\frac{8 \pi R^3 \rho g}{3 k}$
$(C)$ the light sphere is partially submerged.
$(D)$ the light sphere is completely submerged.
- 2View SolutionThe pans of a physical balance are in equilibrium. Air is blown under the right hand pan; then the right hand pan will
- 3A liquid flows in the tube from left to right as shown in figure. $A_1$ and $A_2$ are the cross-sections of the portions of the tube as shown. The ratio of speed $\frac{v_1}{v_2}$ will be ..........View Solution
- 4Determine the pressure difference in tube of non$-$uniform cross sectional area as shown in figure. $\Delta P =?$ (in $pa$)View Solution
$d_{1}=5\, cm , V_{1}=4\, cm , d_{2}=2\, cm , V_{2}=?$
- 5In a cylindrical water tank, there are two small holes $A$ and $B$ on the wall at a depth of $h_1$ , from the surface of water and at a height of $h_2$ from the bottom of water tank. Surface of water is at height of $h_2$ from the bottom of water tank. Surface of water is at heigh $H$ from the bottom of water tank. Water coming out from both holes strikes the ground at the same point $S$. Find the ratio of $h_1$ and $h_2$View Solution
- 6Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is $36 g $ and its density is $9 g / cm^3$. If the mass of the other is $48 g$, its density in $g / cm^3$ isView Solution
- 7Two non-mixing liquids of densities $\rho $ and $n \rho \,(n > 1)$ are put in a container. The height of each liquid is $h.$ A solid cylinder of length $L$ and density $d$ is put in this container. The cylinder floats with its axis vertical and length $\rho L (\rho < 1)$ in the denser liquid. The density $d$ is equal toView Solution
- 8Alarge tank is filled with water to a height $H$.A small hole is made at the base of the tank. It takes $T_1$ time to decrease the height of water to $H/ \eta , (\eta > 1)$ and it takes $T_2$ time to take out the rest of water. If $T_1 = T_2$ , then the value of $\eta$ is :View Solution
- 9Acontainer of large surface area is filled with liquid of density $\rho$ .Acubical block of side edge $a$ and mass $M$ is floating in it with four-fifth of its volume submerged. If a coin of mass $m$ is placed gently on the top surface of the block is just submerged. $M$ isView Solution
- 10Karman line is a theoretical construct that separates the earth's atmosphere from outer space. It is defined to be the height at which the lift on an aircraft flying at the speed of a polar satellite $(8 \,km / s )$ is equal to its weight. Taking a fighter aircraft of wing area $30 \,m ^2$, and mass $7500 \,kg$, the height of the Karman line above the ground will be in the range .............. $km$ (assume the density of air at height $h$ above ground to be $\rho( h )=1.2 e ^{\frac{ h }{10}} \,kg / m ^3$ where $h$ is in $km$ and the lift force to be $\frac{1}{2} \rho v^2 A$, where $v$ is the speed of the aircraft and $A$ its wing area).View Solution