A liquid flows in the tube from left to right as shown in figure. $A_1$ and $A_2$ are the cross-sections of the portions of the tube as shown. The ratio of speed $\frac{v_1}{v_2}$ will be ..........
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(b)
By equation of continuity
$v_1 A_1=v_2 A_2$
So, $\frac{v_1}{v_2}=\frac{A_2}{A_1}$
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