Amplitude, $\mathrm{A}=1 \mathrm{cm}$

Average velocity in the interval in which body moves from equilibrium to half of its amplitude, $\mathrm{v}=?$

Time taken to a displacement $A/2$ where $A$ is the amplitude of oscillation from the

mean position $^{\prime} \mathrm{O}^{\prime}$ is $\frac{\mathrm{T}}{12}$

Therefore, time, $t=\frac{0.5}{12} \mathrm{sec}$

Displacement, $s=\frac{A}{2}=\frac{1}{2} c m$

Average velocity, $v=\frac{\frac{A}{2}}{t}=\frac{\frac{1}{2}}{\frac{0.5}{12}}=12 \mathrm{cm} / \mathrm{s}$