MCQ
A body is projected at such an angle that the horizontal range is three times the greatest height. The angle of projection is
- A${25^o}8'$
- B${33^o}7'$
- C${42^o}8'$
- ✓${53^o}8'$
If $R=3H $ then $\cot \theta = \frac{3}{4} ⇒ \theta = 53^\circ 8'$
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