A body of mass $1\,kg$ is executing simple harmonic motion. Its displacement $y(cm)$ at $t$ seconds is given by $y = 6\sin (100t + \pi /4)$. Its maximum kinetic energy is ..... $J$
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(b) So $a = 6cm,\;\omega = 100\,rad/\sec $
${K_{\max }} = \frac{1}{2}m{\omega ^2}{a^2}$
${K_{\max }} = \frac{1}{2}m{\omega ^2}{a^2}$
$= \frac{1}{2} \times 1 \times {(100)^2} \times {(6 \times {10^{ - 2}})^2} $
$= 18\;J$
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